User Defined Java Expression
Description
This step allows you to enter User Defined Java Expressions as a basis for the calculation of new values.
If you have a Java expression like :
C=A+B
Then you can simply enter the right side of the expression in the dialog:
A+B
 The values are exposed to the expressions as the Java objects they are :
Data type |
Java Class |
---|---|
String |
java.lang.String |
Integer |
java.lang.Long |
Number |
java.lang.Double |
Date |
java.util.Date |
BigNumber |
BigDecimal |
Binary |
byte[] |
Options
Options |
Description |
---|---|
New Field |
The new field in the data stream. If you want to overwrite an existing field, you need to define the field here and in the "Replace value" option. |
Java Expression |
The Java Expression, see examples below |
Value Type |
Type |
Length |
Length |
Precision |
Precision |
Replace value |
Select this identical to the "New field" name when you want to replace the |
Metadata Injection Support
All fields of this step support metadata injection. You can use this step with ETL Metadata Injection to pass metadata to your transformation at runtime.
Examples
Add 2 integers, A and B
A+B
Concatenate 2 Strings : firstname and name and put a space in between
firstname+" "+name
or if you really care about performance, this might be faster:
new StringBuffer(firstname).append(" ").append(name).toString()
Set the first character of each word in upper-case: john doe --> John Doe
org.pentaho.di.core.Const.initCap(name)
Use native Java and API functions
System.getProperty("os.name")
When the used method throws an exception, you need at minimum PDI 3.2.1, see PDI-2611
Business rules (If / Then / Else)
When a<c then return true else return false
a<c?true:false
This can be more complicated
a<c?(a==1?1:2):3
even with OR and AND and other operators and functions
Using Constants
If you use a constant, you may need to define the right type in some expressions otherwise it could throw:
Incompatible expression types "int" and "java.lang.Long"
To solve this, use:
test == null ? new Long(0) : test
In this case, it checks if test is null and replaces with zero. If it is not null, it will return test.
If the return value is a BigNumber (BigDecimal), you need at minimum PDI 3.2.3, see PDI-2910
Cut a string from end and test for null and minimal length
Imagine you have input strings with
- Orlando FL
- New York NY
and you want to separate the state and city, you could use the following expressions:
For state (get the last 2 characters):
location != null && location.length()>2 ? location.substring(location.length()-2, location.length()) : null
For city (get the beginning without the last 2 characters and trim):
location != null && location.length()>2 ? location.substring(0, location.length()-2).trim() : location
Within the code there is a check for null and a minimal length of 2, the complete example is attached to an enhancement request PDI-6915.
Functionality of a LIKE operator (contains string)Â and replacing values
The following example returns 1 when abc is within the source string, otherwise 2. It returns also 2 when the source string is null. The return values could be of value type Integer.
samplestr !=null && samplestr.indexOf("abc")>-1 ? 1 : 2
The complete example is attached to an enhancement request PDI-1241.